Respuesta :
Answer:
The confidence interval for the mean is given by the following formula: Â
[tex]\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}[/tex]
Where :
[tex] \hat p[/tex] represent the point of estimate
And [tex] ME = z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}[/tex] represent the margin of error
For this reason the confidence interval is the point of estimates plus/minus the margin of error
D.) ​point estimate, margin of error
Step-by-step explanation:
Previous concepts
A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval". Â
The margin of error is the range of values below and above the sample statistic in a confidence interval. Â
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean". Â
The population proportion have the following distribution
[tex]p \sim N(p,\sqrt{\frac{p(1-p)}{n}})[/tex]
Solution to the problem
The confidence interval for the mean is given by the following formula: Â
[tex]\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}[/tex]
Where :
[tex] \hat p[/tex] represent the point of estimate
And [tex] ME = z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}[/tex] represent the margin of error
For this reason the confidence interval is the point of estimates plus/minus the margin of error
D.) ​point estimate, margin of error
