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What is the change in temperature when 3.00 grams of calcium chloride is dissolved in 100 mL of water?
5.19
oC

Given the change in the temperature from adding 3.00 grams of calcium chloride to 100.00 mL of water( 5.19), calculate the enthalpy of solution for calcium chloride in units of kJ/mol.
kJ/mol

Respuesta :

akindeleot

Answer:

82.74 kJ/mol

Explanation:

Mass of Water = 100 mL == 100 g

Mass of CaClâ‚‚ = 3 g

Total solution mass = Hâ‚‚O mass + CaClâ‚‚ mass = 103 g

Heat capacity is same as that of water 4.184 J/g °C

∴ Heat released on dissolution = Mass x Specific heat x ΔTemperature

       = 103 g x 4.184 J/g °C x 5.19 °C

       = 2236.64 J

Molar mass of CaClâ‚‚ = 110.98 g/mol

∴ Heat released on dissolution of a mol of CaCl₂

       = (2236.64 J /  3.0 g) x 110.98 g/mol

       = 82740.769 J/mol

In KiloJoules = 82.74 kJ/mol

The enthalpy of solution for calcium chloride is 82.74 kJ/mol.The specific heat capacity is the heat or energy required to change one unit mass of a substance

Given:

Mass of Water = 100 mL == 100 g

Mass of CaClâ‚‚ = 3 g

Total solution mass = Hâ‚‚O mass + CaClâ‚‚ mass = 103 g

Heat capacity is same as that of water 4.184 J/g °C

Specific heat:

∴ Heat released on dissolution = Mass * Specific heat * ΔTemperature

Heat released = 103 g x 4.184 J/g °C x 5.19 °C

Heat released = 2236.64 J

Molar mass of CaClâ‚‚ = 110.98 g/mol

∴ Heat released on dissolution of a mol of CaCl₂

Heat released= (2236.64 J /  3.0 g) x 110.98 g/mol

Heat released= 82740.769 J/mol

The heat released in KiloJoules = 82.74 kJ/mol

Find more information about specific heat here:

brainly.com/question/13439286

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