Given the data from the question,
A. The number of mole of water needed for the reaction is 1 mole
Bi. The number of mole of Câ‚‚Hâ‚‚ formed is 0.5 mole
Bii. The number of mole of Ca(OH)â‚‚ formed is 0.5 mole
Mole = mass / molar mass
Mole of CaCâ‚‚ = 32 / 64
Mole of CaCâ‚‚ = 0.5 mole
Balanced equation
CaC₂ + 2H₂O —> C₂H₂ + Ca(OH)₂
From the balanced equation above,
1 mole of CaCâ‚‚ required 2 moles of Hâ‚‚O
Therefore,
0.5 mole of CaC₂ will require = 0.5 × 2 = 1 mole of H₂O
Thus, 1 mole of Hâ‚‚O is needed for the reaction.
Balanced equation
CaC₂ + 2H₂O —> C₂H₂ + Ca(OH)₂
From the balanced equation above,
1 mole of CaCâ‚‚ reacted to produce 1 mole of Câ‚‚Hâ‚‚
Therefore,
0.5 mole of CaCâ‚‚ will also react to produce 0.5 mole of Câ‚‚Hâ‚‚
Thus, 0.5 mole of Câ‚‚Hâ‚‚ was obtained from the reaction
Balanced equation
CaC₂ + 2H₂O —> C₂H₂ + Ca(OH)₂
From the balanced equation above,
1 mole of CaCâ‚‚ reacted to produce 1 mole of Ca(OH)â‚‚
Therefore,
0.5 mole of CaCâ‚‚ will also react to produce 0.5 mole of Ca(OH)â‚‚
Thus, 0.5 mole of Ca(OH)â‚‚ was obtained from the reaction
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