Answer:
17.6510 L
Explanation:
First we should get the number of moles of helium here by Boyle's law
PV=nRT
P=750/760= 0.9868 atm
T=25+273=298 kelvin
R= 0.08206
V= 20L
so
n=PV/RT
n=0.9868Ă—20/0.08206Ă—298
n=0.80707 mol
Then use the same law
V=0.80707Ă—0.08206Ă—263/0.9869=
17.6510L
SO THE VOLUME WILL BE 17.6510 L