Which series of transformations will not map figure Q onto itself?
O(x+2, y-2), reflection over y = x - 1
O(x-2, y + 2), reflection over y = x + 3
O(x+0y-4), reflection over y = x - 1
O(x-3, y-3), reflection over y = -x +1
Question 1 (Answered)
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Which series of transformations will not map figure H onto itself?

A. O(x+0, y-2), reflection over y = 1

B. O(x+2, y-0), reflection over x=3

C. O(x+3, y+3), reflection over y = -x +7

D. O(x-3, y-3), reflection over y = -x +2

The correct option is Option D: the series of transformation O(x-3, y-3), reflection over y = -x +2 will not map figure H onto itself.

Here given a square with its 4 vertices at coordinates (2,1), (1,2), (2,3) and (3,2).

By checking all the options

Option A:

1st transformation (x+0, y-2) will map 4 vertices of the square into points of coordinates such as

(2,1) β†’ (2,-1)

(1,2) β†’ (1,0)

(2,3) β†’ (2,1)

(3,2) β†’ (3,0)

next transformation which is the reflection over y=1 gives the coordinates (x,2-y)

(2,-1) β†’ (2,3)

(1,0) β†’ (1,2)

(2,1) β†’ (2,1)

(3,0) β†’ (3,2)

These new points are exactly the same as the vertices of the initial square.

Option B:

1st transformation (x+2, y-0) will map 4 vertices of the square into points of coordinates such as

(2,1) β†’ (4,1)

(1,2) β†’ (3,2)

(2,3) β†’ (4,3)

(3,2) β†’ (5,2)

next transformation which is the reflection over x=3 gives the coordinates (6-x,y)

(4,1) β†’ (2,1)

(3,2) β†’ (3,2)

(4,3) β†’ (2,3)

(5,2) β†’ (1,2)

These new points are exactly the same as the vertices of the initial square.

Option C:

1st transformation (x+3, y+3) will map 4 vertices of the square into points of coordinates such as

(2,1) β†’ (5,4)

(1,2) β†’ (4,5)

(2,3) β†’ (5,6)

(3,2) β†’ (6,5)

next transformation which is the reflection over y=-x+7 gives the coordinates such as

(5,4) β†’ (3,2)

(4,5) β†’ (2,3)

(5,6) β†’ (1,2)

(6,5) β†’ (2,1)

These new points are exactly the same as the vertices of the initial square.

Option D:

1st transformation (x-3, y-3) will map 4 vertices of the square into points of coordinates such as

(2,1) β†’ (-1,-2)

(1,2) β†’ (-2,-1)

(2,3) β†’ (-1,0)

(3,2) β†’ (0,-1)

next transformation which is the reflection over y=-x+2 gives the coordinates such as

(-1,-2) β†’ (4,3)

(-2,-1) β†’ (3,4)

(-1,0) β†’ (2,3)

(0,-1) β†’ (3,2)

These new points are not matching with the vertices of the initial square.

Therefore the correct option is Option D: O(x-3, y-3), reflection over y = -x +2 will not map figure H onto itself.

Learn more about transformation

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