How many liters of 4.0 M NaOH solution are needed to prepare 1.0 L of a 0.50 M NaOH solution

M_1 is given to be 4 M, and V_1 is what the problem wants. M_2 is .5 M and V_2 is 1 L. Plugging these into the equation gives us 4(V_1) = .5(1). 4/.5=8

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dulcerios25 dulcerios25 · Answer 2 · 2024-03-01T08:01:06+01:00

0.125 L (with no sig figs)

I’m not sure if you’re familiar with the formula M1 x V1 = M2 x V2, but that is what will be using here.

Another good one to know is that moles= MV
(moles = Molarity times volume)

M is for Molarity and V is for volume, volume typically uses liters. So for this example we can set up an equation to find x. x L(4.0 M) = 1.0 L ( 0.50 M)

We multiply on the right.

x L (4.0 M) = 0.5 moles

And now divide both sides by 4.0

x = 0.5/4.0

x = 0.125 L