Isabella10 Isabella10

03-11-2015
Mathematics

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5 consecutive intergers whose sum is 195

Respuesta :

03-11-2015

x + (x+1) + (x+2) + (x+3) + (x+4) = 195

5x + 10 = 195

5(x+2) = 195

x + 2 = 39

x = 37

The 5 consecutive integers whose sum is 195 are 37, 38, 39, 40, 41.

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