The balanced equation for the reaction is as follows; Li₂O + H₂O ---> 2LiOH Stoichiometry of Li₂O to H₂O is 1:1 Mass of Li₂O reacted - 18.9 g Number of Li₂O moles reacted - 18.9 g / 30 g/mol = 0.63 mol An equivalent amount of moles of water have reacted - 0.63 mol mass of water required - 0.63 mol x 18 g/mol = 11.34 g A mass of 11.34 g of water is required
